Will lead (#Pb#) react with #HgSO_4#?
We need to combine two distinct reduction reactions for mercury, so let's look at their standard reduction potentials.
The first two are nullified to obtain:
where
and the electrons must be eliminated.
In this instance, it's not too tough because mercury has a much higher reduction potential, which makes it easier to reduce and a useful oxidizing agent.
Consequently, to obtain the complete response, add back the spectator anion:
Remember that mercury (II) sulfate appears to break down in water, so you would likely need to use a different solvent for this.
Although I anticipate that the reduction potentials will vary, their relativities ought to hold steady (that is, mercury(II) should continue to have a greater reduction potential than iron(II).
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No, lead (Pb) will not react with HgSO₄.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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