Why isn't the answer parallelogram?

(I am aware a rhombus is a type of parallelogram). Can someone please simply explain? Thank you! I have an exam soon.

Oh yeah: Slope of CD is 0 and Slope of AD is 4/3

Answer 1

#ABCD# is a rhombus.

You have to prove that the diagonals cut at right angles. Then it is a rhombus.

Let the point of intersection of the diagonals be #O#
The height is #=4#

We have

#AB=BC=CD=DA=5#
Diagonal, #AC=sqrt(8^2+4^2)=sqrt80#

So,

#AO=sqrt80/2=sqrt20#
Diagonal, #BD=sqrt(4^2+2^2)=sqrt20#
#BO=sqrt20/2=sqrt5#

So,

In the triangle #AOB#
#AO=sqrt20#
#BO=sqrt5#
and #AB=5#
#AO^2+BO^2=20+5=25=AB^2#

Therefore,

the triangle #AOB# is right triangle ( inverse theorem of Pythagoras)
So, #ABCD# is a rhombus.
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Answer 2

The answer isn't parallelogram because the given question likely pertains to a specific context or problem where the properties or conditions of a parallelogram do not apply. Without further details or context, it's challenging to provide a precise explanation for why parallelogram isn't the correct answer.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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