Why in formaldehyde (#CH_2O#) are hydrogens attached to the Carbon atom and not oxygen?
Because if they were, oxygen would be positively charged and carbon would be unstably negative. Atoms don't simply bond without regard for charge and electron count. They must obey the laws of nature.
Your isomeric possibilities are:
-
Naturally, the first one is the most stable. It is positively-polarized towards carbon, and thus, carbon becomes the site for nucleophilic attack, such as by
#"CH"_3"CH"_2"O"^(-)# , or#"CN"^(-)# . -
The second one is unreasonable because of the electronegativities of carbon (
#"2.5# ) and oxygen (#"3.5# ).
Oxygen is more electronegative, so there is no reason why it would favorably be positively-charged (unless it were to be protonated by a strong acid in the true structure of formaldehyde), and likewise, carbon would prefer to be the one that is partially positive (in fact, it is).
- The third structure is impossibly unreasonable for the same reasons as above. The formal charges are, of course, not minimized, when they can and should be, as in structure 1.
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The carbon atom in formaldehyde (CH₂O) forms a double bond with oxygen, leaving only one available bonding site for hydrogen atoms on the carbon atom. Oxygen, being more electronegative than carbon, attracts the electrons in the bond more strongly, making it less favorable for hydrogen to bond directly with oxygen in this molecular arrangement.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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