Why does magnesium for #Mg^(2+)# cations and not #Mg^(6-)# anions?
Because magnesium is a metallic element that tends to loss electron to achieve stability.
Group 2 includes magnesium, which likewise has a valence electron of 2. In order to follow the octet rule and achieve stability, these two electrons in the outer shell will be removed, converting the atom into an ion with a 2+ charge.
By signing up, you agree to our Terms of Service and Privacy Policy
Magnesium has two electrons in its outer shell, which it tends to lose to achieve a stable electron configuration. This results in the formation of Mg^(2+) cations rather than Mg^(6-) anions.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- When methanol is burned and leaves a residue is this a chemical or pyhsical change?
- How can the atomic number of nitrogen be determined?
- Is it possible for two different substances to contain the same number of protons but different atomic numbers?
- What mixture type is characterized by the settling of particles?
- How many types of atoms are in carbon?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7