Why do CaCO3 + CO2 + H2O form Ca(HCO3)2?

Is it because CO2 + H2O create the carbonic acid H2CO3 and it somehow reacts with CaCO3?

Answer 1

Considering poor solubility of #CaCO_3(s)# a probable explanation may be given as follows

Calcium carbonate is poorly soluble in pure water (47 mg/L) Ksp = 3.7×10−9 to 8.7×10−9 at #25^oC# there exist an ionic equilibrium with the ions formed due to ionization of soluble calcium carbonate. #CaCO_3(s) ⇌CO_3(soln) ⇌ Ca^(2+)(aq) + CO_3^(2−)(aq)# Now in presence of #CO_2# in water #H_2CO_3# is formed and as a result medium becomes acidic. In this acidic medium there exists #HCO_3^-# ion and #H^+#.The #CO_3^(2−)(aq)#ions get protonated by this#H^+# ions and #HCO_3^-# ions are formed .So decrease in concentration of #CO_3^(2−)(aq)#ions in solution shifts the above equilibrium towards right and dissolution of more #CaCO_3(s)# in solution takes place. And the reaction proceeds as stated in question.

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Answer 2

CaCO3 + CO2 + H2O form Ca(HCO3)2 because when carbon dioxide dissolves in water, it forms carbonic acid (H2CO3), which then reacts with the calcium carbonate (CaCO3) to produce calcium bicarbonate (Ca(HCO3)2). This reaction occurs in natural settings, such as in the dissolution of limestone by carbonic acid in rainwater.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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