Why do you need to balance a chemical equation?
A knowledge of basic arithmetic.
Mass is conserved in all chemical reactions, so if I start with 10 g of reactant at most, I can finish with 10 g of product. In reality, though, I won't even get that because handling losses occur....and also a properly balanced chemical equation to establish stoichiometry.
Let's take a basic equation:
This clearly indicates that 18 g of water are produced when 2 g of dihydrogen and 16 g of dioxygen react. It is also obvious that mass has been preserved, as stoichiometry requires.
Here's a task for you, then:
The mass and charge balances in the following equation
How many grams of dioxygen are needed if I burn 16 grams of methane, and how many grams of carbon dioxide gas will be produced?
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Balancing a chemical equation is necessary to ensure that the law of conservation of mass is obeyed. This law states that matter cannot be created or destroyed in a chemical reaction, only rearranged. By balancing the equation, the number of atoms of each element on the reactant side must be equal to the number of atoms of the same element on the product side, ensuring that mass is conserved.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- Consider the following reaction: #CaCO_3+SO_2 to CaSO_3+CO_2#. Here #SO_2# is oxidized to #CaSO_3#, so is #SO_2# a reducing agent or oxidizing agent? Kindly give your reason.
- By means of a stoichiometric equation, how would the precipitation of cadmium hydroxide be represented?
- How would you balance the equation for the combustion of octane: C8H18(l)+O2(g)---->CO2(g)+H2O(l)?
- What is the balanced chemical equation using the diagram below?
- What are the two parts of a chemical reaction?

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