Why do haloalkanes undergo nucleophilic substitution?
Haloalkanes undergo nucleophilic substitution because their electronegativity puts a partial positive charge on the α carbon atom.
All the halogens except iodine are more electronegative than carbon. Iodine has the same electronegativity as carbon.
That means that every carbon-halogen bond (except C-I) will have a δ⁺ charge on the carbon.
The positive charge makes that carbon susceptible to attack by a nucleophile.
Although the C-I bond is nonpolar, it is highly polarizable.
Imagine a negative ion approaching the bond from the back side of the carbon atom:
The approaching negative ion repels the electrons of the C-I bind and induces a δ⁺ charge on the carbon.
So alkyl iodides also undergo nucleophilic substitution.
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Haloalkanes undergo nucleophilic substitution due to the electrophilic nature of the carbon-halogen bond, where a nucleophile displaces the halogen, forming a new bond with carbon. This reaction is influenced by factors such as nucleophile strength, leaving group ability, and steric hindrance.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- Is there a requirement for the stereochemistry of the starting material in E1 reactions? Why?

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