Why can an anti-markovnikov radical addition of haloalkane only happen in presence of hydrogen peroxide?
In a "normal" Markovnikov attrition of
In the peroxide-catalyzed addition, the bromine radical adds to the carbon with more hydrogen atoms in order to form the more stable radical.
That means that the
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The presence of hydrogen peroxide facilitates the formation of a radical initiator, which generates radicals. These radicals undergo anti-Markovnikov addition with haloalkanes, resulting in the anti-Markovnikov product.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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