Which two numbers will complete the pattern? 3328,832,208

Answer 1

# "The next 2 numbers are:" \qquad \qquad 52 \qquad "and" \qquad 13. #

# "This is a nice question !" #
# "It looks to me like you go from one number to the next by" # # "dividing by 4:" #
# \qquad \qquad \qquad \qquad 3328 \div 4 = 832, \qquad 832 \div 4 = 208. #
# "So, to get the next 2 numbers, we continue the same:" #
# \qquad \qquad \qquad \qquad 208 \div 4 = 52, \qquad 52 \div 4 = 13. #
# "So, the next 2 numbers are:" #
# \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad \quad 52 \qquad "and" \qquad 13. #
# "[Extra Note: because 13 is not divisible by 4, we cannot go" # # "any further, unless we want to include fractions as Ok.]" #
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Answer 2

The pattern appears to involve dividing each number by 4. So, to continue the pattern, the next two numbers would be ( \frac{208}{4} = 52 ) and ( \frac{52}{4} = 13 ). Therefore, the two numbers that complete the pattern are 52 and 13.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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