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Which of the ordered pairs is a solution for the equation 4x - 2y = 8 (0,4), (-2,0) (-2,-4)(0,-4)?

Answer 1

#(0, 4)#

You have to check if the ordered pair is true for the given equation So given #4x -2y =8# Firstly re-arrange this to #2y = 4x - 8# which can then be divided by 2 to give #y = 2x - 4# Now check each ordered pair for #(0, 4)# substitute # x = 4# into the Rihgt hand Side (RHS) to get #(2xx4) - 4 = 8 - 4 = 4# So for this pair #y = 4# and the pair satisfies the equation Now check #(-2, 0)# in the same way When #x = -2# RHS = #(4xx -2) - 4 = -12# which does not equal LHS = 0 Now check #(-2 , -4)# the x valie is the same as before, so this does not work either Lastly check #(0, -4)# but this does not equal the RHS when #x = 0# either So the only solution is #(0, 4)#

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Answer 2

Jace Anderson

(0,4)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.