Which of the following compounds is most reactive to an aqueous solution of sodium carbonate ?

Answer 1

Compound 3

Compound 3 will be most reactive towards aqueous solution of sodium carbonate because it is most acidic among the given set of compounds. The main cause of the acidity is that the anion formed after the removal of proton from compound 3 is aromatic.

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Answer 2

To determine which compound is most reactive to an aqueous solution of sodium carbonate, we need to identify compounds that are acidic and likely to undergo a reaction with the sodium carbonate solution to produce carbon dioxide gas.

The compounds that are most likely to react with sodium carbonate solution are acidic compounds. In general, acidic compounds contain hydrogen ions (( H^+ )) that can react with carbonate ions (( CO_3^{2-} )) in the sodium carbonate solution to produce carbon dioxide gas (( CO_2 )), water (( H_2O )), and a salt.

So, among the given compounds, the one that is acidic or contains acidic functional groups is most likely to be the most reactive with sodium carbonate solution.

If the list of compounds was provided, I could identify the specific compound that is most reactive to the aqueous solution of sodium carbonate based on its acidity. Without the list of compounds, it's not possible to determine the most reactive compound.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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