Which Gas Law is involved when a balloon pops after sitting on it?

Answer 1

Boyle's Law.

The primary ideal gas law involved in this event is #p*V = const# Here #p# is a pressure and #V# is a volume of an ideal gas. When you sit on a balloon you decrease the volume . Therefore, the pressure must increase and, when it is too high, the balloon cannot hold it anymore and pops.

The law mentioned above is known as Boyle's Law. It applies when an ideal gas's temperature stays constant. The two ideal gas laws that follow apply when the temperature varies.

Gay-Lussac's Law (if the volume occupied by gas does not change) #p/T = const#
Combined Ideal Gas Law (if all three characteristics of an ideal gas, its temperature , volume and pressure change) #(p*V)/T = const#

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Answer 2

The gas law involved when a balloon pops after sitting on it is Boyle's Law.

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Answer 3

When a balloon pops after sitting on it, the gas law involved is Boyle's Law.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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