When you solve an equation like sin x = 0,5 why do you have to write both solutions and not just +- 30 + n * 360?

Answer 1

Mostly because #sin(-30^@) != 0.5#

The solutions to #sinx=0.5# (for angles, in degrees) are
#-690^@, -330^@, 30^@, 390^@, 750^@# --that is #30^@ +n360^@#

and

#-570^@, -210^@, 150^@, 510^@, 870^@# --that is #150^@ +n360^@#
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Answer 2

When solving equations like (\sin(x) = 0.5), you typically need to find all solutions within a specified interval. In this case, the interval is usually taken to be from (0) to (360) degrees or (0) to (2\pi) radians.

Since the sine function is periodic, it repeats its values every (360) degrees or (2\pi) radians. Therefore, when finding solutions, you should consider all possible repetitions of solutions within this interval.

Using ( \pm 30 + n \times 360 ) gives you only one solution set, but it doesn't cover all possible solutions within the specified interval. To find all solutions, you need to consider all possible repetitions of the solution within the interval, which is why you would write multiple solutions instead of just one.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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