When the following equation is balanced, what is the coefficient for Mg? #Mg(s) + HCl(aq) -> MgCl_2(aq) + H_2(g)#

Answer 1

Peyton Adams

1 is the coefficient. See below.

Thus, we make the number of each element equal on both sides of a chemical equation to achieve equilibrium.

We have: #Mg (s) + HCl (aq) → MgCl_2 (aq) + H_2 (g)#

LHS Cl= 1 H= 1 Mg = 1.

RHS Mg = 1 Cl = 2 H = 2

We place a 2 in front of the HCl so that Cl and H have two on both sides.

#Mg (s) + 2HCl (aq) → MgCl_2 (aq) + H_2 (g)#

LHS Cl=2, H=1, and Mg=

RHS Cl=2, H=1, and Mg=1

The final equation does not include the coefficient of magnesium (Mg), as it is understood that the equation is balanced.

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Answer 2

Axel Alvarado

The balanced equation is:

[ \text{Mg}(s) + 2\text{HCl(aq)} \rightarrow \text{MgCl}_2(aq) + \text{H}_2(g) ]

Therefore, the coefficient for Mg is 1.

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Answer 3

Cooper Anderson

The coefficient for Mg in the balanced equation is 1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When the following equation is balanced, what is the coefficient for Mg? #Mg(s) + HCl(aq) -&gt; MgCl_2(aq) + H_2(g)#

When the following equation is balanced, what is the coefficient for Mg? #Mg(s) + HCl(aq) -> MgCl_2(aq) + H_2(g)#