When a number x is added to its square, the total is 12. How do you find two possible values for x?

Answer 1

#x=-3, 4#

#x^2+x=12 rarr# Subtract 12 from each side
#x^2+x-12 rarr# This equation is in standard form: #ax^2+bx+c#

To solve this, we can graph, use the quadratic formula, or use the "big X" method (I'll use the third)

Think of two numbers that multiply to #c# (in this case, -12) and add up to #a*b# (in this case, 1): #-3 and 4#
#(x-3)(x+4)=0#
#x-3=0#
#x=3#
#x+4=0#
#x=-4#
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Answer 2

To find two possible values for ( x ), solve the equation ( x + x^2 = 12 ) using factoring, completing the square, or the quadratic formula.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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