When 56.6 g of calcium is reacted with nitrogen gas, 32.4 g of calcium nitride is produced. What is the percent yield of calcium nitride in the reaction #3Ca(s) + N_2(g) -> Ca_3N_2(s)#?

To calculate the percent yield of calcium nitride, we first need to determine the theoretical yield of calcium nitride using stoichiometry.

1. Calculate the molar mass of calcium nitride (Ca₃N₂): Molar mass of Ca = 40.08 g/mol Molar mass of N = 14.01 g/mol Total molar mass of Ca₃N₂ = (340.08) + (214.01) = 120.24 + 28.02 = 148.26 g/mol

2. Calculate the number of moles of calcium used: Given mass of calcium = 56.6 g Molar mass of calcium = 40.08 g/mol Number of moles of calcium = 56.6 g / 40.08 g/mol = 1.41 mol

3. Use the stoichiometric coefficients from the balanced equation to find the theoretical yield of calcium nitride: From the balanced equation: 3 moles of Ca produce 1 mole of Ca₃N₂ Therefore, 1.41 moles of Ca would produce (1/3) * 1.41 = 0.47 moles of Ca₃N₂

4. Calculate the theoretical yield of calcium nitride in grams: Theoretical yield (in grams) = number of moles * molar mass Theoretical yield = 0.47 mol * 148.26 g/mol = 69.66 g

5. Calculate the percent yield using the given and theoretical yields: Percent yield = (actual yield / theoretical yield) * 100% Percent yield = (32.4 g / 69.66 g) * 100% ≈ 46.52%

Therefore, the percent yield of calcium nitride in the reaction is approximately 46.52%.