# When 3 grams of #"NaCl"# are added to 75.25 grams of water, what is the change in the water's freezing point?

As its name suggests, the freezing-point depression tells you by how many degrees the freezing point of the solution will decrease compared with that of the pure solvent.

The equation that allows you to calculate freezing-point depression looks like this

Here

Water's cryoscopic constant is listed as

This means that the van't Hoff factor, which tells you the ratio that exists between the number of moles of solute dissolved and the number of particles of solute produced in solution, will be equal to

Use sodium chloride's molar mass to convert the grams of solute to moles

Convert the mass of water from grams to kilograms

The molality of the solution will be equal to

I'll leave the answer rounded to two sig figs, but don't forget that you have one sig fig for the mass of sodium chloride.

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The change in the water's freezing point, when 3 grams of NaCl are added to 75.25 grams of water, is approximately -1.86°C.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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