When 20.0 g of sodium fluoride is dissolved in water to prepare the total volume of 200.0 mL solution, what is the molarity of the solution?
The molarity of the solution is 2.38 mol/L
Since molar concentration (molarity) is defined as moles of solute per litre of solution, we will first have to convert the mass of the NaF (molar mass = 42 g) into moles:
Now, we divide:
Molarity = ("moles of solute")/("litres of solution")
#= 0.476 "mol"/ 0.200 L = 2.38 mol/L
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To find the molarity of the solution, we first need to calculate the number of moles of sodium fluoride (NaF) present in the solution, and then divide that by the total volume of the solution in liters.
Given:
- Mass of sodium fluoride (NaF) = 20.0 g
- Volume of solution = 200.0 mL = 0.200 L
The molar mass of sodium fluoride (NaF) is approximately 41.99 g/mol.
Now, we can calculate the number of moles of NaF:
[ \text{Number of moles} = \frac{\text{Mass}}{\text{Molar mass}} ]
[ \text{Number of moles} = \frac{20.0 , \text{g}}{41.99 , \text{g/mol}} \approx 0.476 , \text{mol} ]
Finally, we calculate the molarity (M) using the formula:
[ \text{Molarity} = \frac{\text{Number of moles}}{\text{Volume of solution (in liters)}} ]
[ \text{Molarity} = \frac{0.476 , \text{mol}}{0.200 , \text{L}} = 2.38 , \text{M} ]
So, the molarity of the solution is approximately (2.38 , \text{M}).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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