What will be the volume of 3.65 g of oxygen gas be at STP?
Well...
It should be noted that all elemental gases with any chemistry are diatomic; you just need to KNOW that oxygen is.
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Using the ideal gas law and the molar mass of oxygen gas, we can calculate the volume at STP:

Calculate the number of moles of oxygen gas: Moles = mass / molar mass Moles = 3.65 g / 32.00 g/mol = 0.11406 moles

At STP, 1 mole of gas occupies 22.414 L.

Calculate the volume of 0.11406 moles of oxygen gas at STP: Volume = moles × 22.414 L/mol Volume = 0.11406 moles × 22.414 L/mol = 2.56 L
Therefore, the volume of 3.65 g of oxygen gas at STP is approximately 2.56 liters.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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