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What weight (in grams) of #KCl# is there in 2.50 liters of 0.50M #KCl# solution?

Answer 1

Caleb Adams

#"Mass of solute"# #=# #"Concentration"xx"volume"xx"molar mass of solute"# #~=# #90*g#

#"Moles of solute"# #=# #2.50*Lxx0.50*mol*L^-1# #=# #1.25*mol#.

#"Mass of solute"# #=# #1.25*molxx74.55*g*mol^-1# #=# #??g#

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Answer 2

Cooper Anderson

To calculate the weight of KCl in grams, you can use the formula:

[ \text{Weight (in grams)} = \text{Molarity} \times \text{Volume (in liters)} \times \text{Molar mass of KCl} ]

Given:

Molarity (( M )) = 0.50 M
Volume (( V )) = 2.50 liters
Molar mass of KCl = 74.55 g/mol

[ \text{Weight (in grams)} = 0.50 , \text{M} \times 2.50 , \text{L} \times 74.55 , \text{g/mol} ] [ \text{Weight (in grams)} = 0.50 \times 2.50 \times 74.55 ] [ \text{Weight (in grams)} = 93.18 , \text{grams} ]

So, there are 93.18 grams of KCl in 2.50 liters of 0.50 M KCl solution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.