# What volume of oxygen is needed to completely combust 2.36 L of methane gas #CH_4#?

A volume of

Garbage out equals garbage in in the combustion reaction, which is stoichiometrically balanced at a given temperature and pressure because equal volumes of gas contain equal numbers of molecules.

You provided the volume of methane gas in your starting conditions, so if we have a volume of methane, it will require DOUBLE the volume of dioxygen gas for stoichiometric reaction.

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To completely combust 2.36 L of methane gas (CH₄), you need 9.44 L of oxygen gas (O₂).

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