What volume of ammonia gas, NH3, in liters is produced at stp by the complete reaction of 100 g of nitrogen N2, with excess hydrogen? N2 + 3H2 ---> 2NH3

Answer 1

Molar mass of #N_2->28" g/mol"#

So 100 g #N_2=(100g)/(28g/"mol")=100/28mol=25/7mol#

The reaction's equation is

#N_2+3H_2->2NH_3#

The stochiometry of this equation reveals that 1 mol #N_2# produces 2 moles #NH_3#having volume #2xx22.4L # at STP ( when reacted with excess #H_2#)

So 100g or.#25/7" mol " N_2# produces #25/7molxx2xx22.4L/"mol"NH_3# #=160" L "NH_3#

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Answer 2

Kai Bowman

Using the balanced chemical equation N2 + 3H2 -> 2NH3, and the given mass of nitrogen (100 g), we can first calculate the moles of nitrogen. Then, using the stoichiometry of the reaction, we can determine the moles of ammonia produced. Finally, we can use the ideal gas law to find the volume of ammonia gas produced at STP.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

What volume of ammonia gas, NH3, in liters is produced at stp by the complete reaction of 100 g of nitrogen N2, with excess hydrogen? N2 + 3H2 ---&gt; 2NH3

What volume of ammonia gas, NH3, in liters is produced at stp by the complete reaction of 100 g of nitrogen N2, with excess hydrogen? N2 + 3H2 ---> 2NH3