What volume is needed to store 0.80 moles of helium gas at 204.6 kPa and 300 K?

Answer 1

The volume of helium gas is #9.76 L#

For this type of question we would use the ideal gas law equation #PxxV = nxxRxxT#.

Now what you want to do is list your known and unknown variables. Our only unknown is the volume of helium gas. Our known variables are P,n,R, and T.

The pressure has the incorrect units because the pressure should be in atmospheres instead of kPa. In order to go from kPa to atm we use the following relationship:

#101.325 kPa = 1 atm#
#(204.6cancel"kPa")/(101.325cancel"kPa")xx1atm# = #2.019atm#
Now all we have to do is rearrange the equation and solve for P like so: #V = (nxxRxxT)/P# #V = (0.80cancel"mol"xx0.0821(Lxxcancel"atm")/(cancel"mo"lxxcancel"K")xx(300cancel"K"))/(2.019cancel"atm")# #V = 9.76 L#
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Answer 2

Using the ideal gas law ( PV = nRT ), where ( P ) is pressure, ( V ) is volume, ( n ) is the number of moles, ( R ) is the gas constant, and ( T ) is temperature in Kelvin:

( V = \frac{nRT}{P} = \frac{(0.80 \text{ mol})(8.31 \text{ kPa} \cdot \text{L/mol} \cdot \text{K})(300 \text{ K})}{204.6 \text{ kPa}} )

( V \approx 9.19 \text{ L} )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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