What volume in liters does 0.136 g of O2 occupy at 20.0 degree C and 748 torr?

Answer 1
The volume will be #"0.104 L"#.
You're dealing with a sample of oxygen gas, #O_2#, at a certain temperature, #"20"^@"C"#, and pressure, #"748 torr"#. To solve for the volume it occupies, use the ideal gas law equation, #PV = nRT#.

The number of moles in that sample can be first calculated using the molar mass of oxygen.

#0.136cancel("g") * "1 mole"/(32.0cancel("g")) = "0.00425 moles"#

Now enter all of your values into the ideal gas law formula, remembering to convert to degrees Kelvin and torr to atm.

#PV = nRT => V = (nRT)/P#
#V = (0.00425cancel("moles") * 0.082(cancel("atm") * "L")/(cancel("mol") * cancel("K")) * (273.15 + 20)cancel("K"))/(748/760cancel("atm"))#
#V = "0.1038 L"#

The response, rounded to three sig figs, is

#V = color(green)("0.104 L")#
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Answer 2

To find the volume of 0.136 g of O2 at 20.0°C and 748 torr, we can use the ideal gas law equation: PV = nRT.

First, we need to find the number of moles of O2 using its molar mass (32.00 g/mol).

n = mass / molar mass n = 0.136 g / 32.00 g/mol n ≈ 0.00425 mol

Next, we rearrange the ideal gas law equation to solve for volume (V):

V = nRT / P

Substitute the known values: n = 0.00425 mol R = 0.0821 L·atm/(K·mol) (the ideal gas constant) T = 20.0°C + 273.15 = 293.15 K P = 748 torr

V = (0.00425 mol) * (0.0821 L·atm/(K·mol)) * (293.15 K) / (748 torr)

Now, solve for V:

V ≈ 0.174 L

Therefore, 0.136 g of O2 occupies approximately 0.174 liters at 20.0°C and 748 torr.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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