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What volume does 22.4 g of chlorine gas occupy at STP?

Answer 1

#7.08 L#

Because we are at STP, we must use the ideal gas law equation #PxxV = nxxRxxT#.

Next, list your known and unknown variables. Our only unknown is the volume of #Cl_2(g)#. Our known variables are P,n,R, and T.

At STP, the temperature is 273K and the pressure is 1 atm. The proportionality constant, R, is equal to 0.0821 #(Lxxatm)/ (molxxK)# The only issue is the mass of #Cl_2(g)#, we need to convert it into moles of #Cl_2(g)# in order to use the formula. #22.4cancel"g" xx (1molCl_2)/(70.90cancel"g")# = 0.316 mol #Cl_2#

Now all we have to do is rearrange the equation and solve for V like so: #V = (nxxRxxT)/P# #V = (0.316molxx0.0821(Lxxatm)/(molxxK)xx(273K))/(1atm)# #V = 7.08 L#

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Answer 2

Noah Aldrich

22.4 liters.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.