What undergoes sn1 reactions?
Tertiary halogenoalkanes.
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Here, the first slow step involves only the heterolytic fission of the C-X bond (where X is the halogen).
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As a result of this fission, you get a tertiary carbocation and
#X^-# . -
It then follows that the nucleophile (like
#OH^-# or#CN^-# ), attacks the carbocation quickly.
This produces the products.
An example involves the reaction of 2-bromo methylpropane with NaOH in water. You get as a result methyl proapan-2-ol and NaBr.
In
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Molecules with a leaving group that can form a stable carbocation undergo SN1 (substitution nucleophilic unimolecular) reactions. This typically includes tertiary alkyl halides, secondary alkyl halides, and occasionally primary alkyl halides under certain conditions.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- Why are alkenyl and alkynyl halides so bad for SN and E reactions?
- What are leaving groups in nucleophilic substitution reactions?

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