What undergoes sn1 reactions?

Answer 1

Tertiary halogenoalkanes.

  • Here, the first slow step involves only the heterolytic fission of the C-X bond (where X is the halogen).

  • As a result of this fission, you get a tertiary carbocation and #X^-#.

  • It then follows that the nucleophile (like #OH^-# or #CN^-#), attacks the carbocation quickly.

This produces the products.

An example involves the reaction of 2-bromo methylpropane with NaOH in water. You get as a result methyl proapan-2-ol and NaBr.

In #S_N1# reactions, the rate of the reaction will only depend on the concentration of the halogenoalkane.

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Answer 2

Molecules with a leaving group that can form a stable carbocation undergo SN1 (substitution nucleophilic unimolecular) reactions. This typically includes tertiary alkyl halides, secondary alkyl halides, and occasionally primary alkyl halides under certain conditions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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