What type of solution forms if 50g of #Pb(NO_3)_2# are dissolved in 100g of water at 20 degrees C?

Answer 1

It quite probably forms a saturated solution.

The majority of the time, nitrates are highly soluble in water.

#Pb(NO_3)_2(s) rightleftharpoonsPb^(2+) + 2NO_3^-#
We know that the solution is saturated if equilibrium quantities of #Pb(NO_3)_2# are in solution. You will have to look up the solubilities of lead nitrate at the given temperature to see that this is indeed the case.
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Answer 2

A saturated solution of lead(II) nitrate (Pb(NO3)2) forms because 50g of Pb(NO3)2 is dissolved in 100g of water, which exceeds the maximum solubility of Pb(NO3)2 at 20 degrees Celsius.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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