What three consecutive integers have a sum of -33?

Answer 1

#-12, -11, -10#

You could solve this by guessing and checking, but such a strategy might be difficult for numbers larger or smaller than #-33#. As such, we will use an algebraic approach to solve this.

We are told that the sum of three consecutive integers is #-33#. Let's call the lowest of these three integers #x#. Since the numbers are consecutive, it must be the case that the next smallest integer is #x+1# and the greatest integer is #x+2#.

So we can rewrite the problem as the algebraic statement #x + (x+1) + (x+2) = -33#. The rest is algebra.

#x + (x+1) + (x+2) = -33# #x + x + 1 + x + 2 = -33# #3x + 3 = -33# #3x = -36# #x = -12#

Our lowest integers is #-12#. It follows that our next two integers are #-11# and #-10#. We confirm that #-12 - 11 - 10 = -23 - 10 = -33#.

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Answer 2

Julia Adams

The three consecutive integers that have a sum of -33 are -12, -11, and -10.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.