# What's the integral of #(tanx)^2#?

It is

#int (tanx)^2dx=int (sin^2x)/cos^2xdx=int (1-cos^2x)/cos^2xdx= int 1/(cos^2x)dx-int 1dx=tanx-x+c#

Take note that the following trigonometric identities were applied.

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The integral of ( (\tan(x))^2 ) with respect to (x) is:

[ \int (\tan(x))^2 , dx = \tan(x) - x + C ]

Where (C) is the constant of integration.

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