What product do you get when you react 3-bromocyclopentene with #NaOCH_2CH_3# dissolved in #HOCH_2CH_3#?

Answer 1

#"Sodium cyclopentadienide?"#

#C_5H_7Br + NaOEt rarr C_5H_6 +NaBrdarr +EtOH#

#C_5H_6 + NaOEt rarr [C_5H_5]^(-)Na^(+) +EtOH#

#"1 equiv"# gives the diene, #C_5H_6#; the 2nd equiv gives cyclopentadienyl anion. These days, in inorganic laboratories, you can prepare #100*g# quantities of base-free #NaCp# simply by boiling up sodium metal with dicyclopentadiene, #C_10H_12#,

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Answer 2

Skylar Alexander

The product of the reaction between 3-bromocyclopentene and NaOCH2CH3 dissolved in HOCH2CH3 is 3-ethoxycyclopentene.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.