What mass of solution containing 5.00% potassium iodide, #KI#, by mass contains 258 mg #KI#?
The answer is rounded to three sig figs.
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To find the mass of the solution containing 5.00% potassium iodide (KI) by mass that contains 258 mg KI, we can set up a proportion:
(258 mg KI) / (mass of solution) = (5.00 g KI) / 100 g
Solving for the mass of the solution:
mass of solution = (258 mg KI) * (100 g) / (5.00 g KI)
mass of solution ≈ 5160 mg
Therefore, the mass of the solution containing 258 mg of KI is approximately 5160 mg.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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