What mass of #CO_2# contains #4.8 xx 10^22# oxygen atoms?

Question

Mateo Aguilar · Accepted Answer

#"1.8 g CO"_2#

Your strategy here will be to

So, you know that one molecule of carbon dioxide contains

This means that the given number of atoms of oxygen would correspond to

#4.8 * 10^(22) color(red)(cancel(color(black)("atoms O"))) * "1 molecule CO"_2/(2color(red)(cancel(color(black)("atoms O"))))#

# = 2.4 * 10^(22)"molecules CO"_2#

Now, one mole of any molecular substance contains exactly #6.022 * 10^(22)# molecules of that substance -- this is known as Avogadro's constant.

In your case, the sample of carbon dioxide molecules contains

#2.4 * 10^(22) color(red)(cancel(color(black)("molecules CO"_2))) * "1 mole CO"_2/(6.022 * 10^(23)color(red)(cancel(color(black)("molecules CO"_2))))#

#= "0.03985 moles CO"_2#

Finally, carbon dioxide has a molar mass of #"44.01 g mol"^(-1)#, which means that your sample will have a mass of

#0.03985 color(red)(cancel(color(black)("moles CO"_2))) * "44.01 g"/(1color(red)(cancel(color(black)("mole CO"_2))))#

# = color(green)(bar(ul(|color(white)(a/a)color(black)("1.8 g")color(white)(a/a)|)))#

The answer is rounded to two sig figs, the number of sig figs you have for the number of atoms of oxygen present in the sample.

Serenity Allen · Answer

undefined To find the mass of CO2 containing 4.8 × 10^22 oxygen atoms, we need to determine the number of moles of oxygen atoms and then use the molar mass of CO2 to find the mass.

1 mole of CO2 contains 1 mole of oxygen atoms, which is approximately 6.022 × 10^23 atoms.

So, the number of moles of oxygen atoms in 4.8 × 10^22 atoms is:

$ \frac{4.8 \times 10^{22}}{6.022 \times 10^{23}} $ moles

Once we have the number of moles of oxygen, we can find the mass using the molar mass of CO2, which is approximately 44 grams per mole.

So, the mass of CO2 containing 4.8 × 10^22 oxygen atoms is:

$ \left( \frac{4.8 \times 10^{22}}{6.022 \times 10^{23}} \right) \times 44 $ grams.