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What mass of carbon dioxide is produced from the complete combustion of #8.50*10^-3# #g# of methane?

Answer 1

Naomi Aronson

3.145 X # 10^-3# g

The following is the equation for methane combustion.

C#H_4# + #O_2# ------> C#O_2# + 2 #H_2#O

Using molar masses, I can write: One mole of methane burned yields one mole of carbon dioxide.

Using ratios and proportions, we can determine that 16 g of methane produces 44 g of carbon dioxide;

mass of C#O_2# = [ 16g C#H_4# / 44 g C# O_2# ] x 8.50 x #10^-3# of C#H_4#

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Answer 2

Henry Antrim

The balanced chemical equation for the combustion of methane (CH4) is:

CH4 + 2O2 -> CO2 + 2H2O

Using the molar masses:

Molar mass of CH4 = 16.04 g/mol Molar mass of CO2 = 44.01 g/mol

1 mole of CH4 produces 1 mole of CO2.

First, calculate the number of moles of CH4:

8.50 * 10^-3 g / 16.04 g/mol = 5.29 * 10^-4 mol

Then, calculate the number of moles of CO2 produced:

5.29 * 10^-4 mol * 1 mol CO2 / 1 mol CH4 = 5.29 * 10^-4 mol CO2

Finally, calculate the mass of CO2 produced:

5.29 * 10^-4 mol * 44.01 g/mol = 0.023 g of CO2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.