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What mass of #C_12H_22O_11# is needed to make 500mL of 0.200M solution?

Answer 1

Henry Antrim

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#

And thus #"moles of solute"# #=# #"concentration "xx" volume"#:

#=500*cancel(mL)xx10^-3cancelL*cancel(mL^-1)xx0.200*mol*cancel(L^-1)#

#=0.100*mol#.

And since #"number of moles"# #=# #"mass"/"molar mass"#

#"Mass"="moles"xx"molar mass"=0.100*cancel(mol)xx342.29*g*cancel(mol^-1)=??g#

So we need approx. #35*g# sucrose.

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Answer 2

Cooper Adams

To calculate the mass of C12H22O11 needed to make a 500mL of 0.200M solution, you can use the formula:

Mass (g) = moles × molar mass

First, calculate the number of moles using the formula:

moles = Molarity × Volume (in liters)

Then, multiply the number of moles by the molar mass of C12H22O11:

Molar mass of C12H22O11 = (12 × 12.01) + (22 × 1.008) + (11 × 16.00) = 342.30 g/mol

Finally, plug in the values:

moles = 0.200 mol/L × 0.500 L = 0.100 mol Mass = 0.100 mol × 342.30 g/mol ≈ 34.23 g

So, approximately 34.23 grams of C12H22O11 is needed to make a 500mL of 0.200M solution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.