# What mass of aluminum contains twice as many atoms as 35.00 grams of copper?

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To find the mass of Al that has twice as many Cu atoms in 35.00 g, count the number of Cu atoms in 35.00 g, multiply that number by two to get the number of Al atoms, and finally find the mass of Al.

Cu atoms

Molar mass of aluminum (26.982 g/mol)

Al atoms:

Al's mass:

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To determine the mass of aluminum that contains twice as many atoms as 35.00 grams of copper, we need to compare the number of atoms in both substances.

First, we need to find the molar mass of each element:

- The molar mass of copper (Cu) is approximately 63.55 grams/mole.
- The molar mass of aluminum (Al) is approximately 26.98 grams/mole.

Next, we calculate the number of moles of copper using its given mass: Number of moles of copper = mass of copper / molar mass of copper = 35.00 grams / 63.55 grams/mole ≈ 0.551 moles

Now, we use Avogadro's number (6.022 × 10^23 atoms/mole) to find the number of atoms in 0.551 moles of copper: Number of atoms of copper = moles of copper × Avogadro's number ≈ 0.551 moles × 6.022 × 10^23 atoms/mole ≈ 3.320 × 10^23 atoms

Since we want to find the mass of aluminum that contains twice as many atoms as this, we multiply the number of copper atoms by 2: Number of atoms of aluminum = 2 × 3.320 × 10^23 atoms ≈ 6.640 × 10^23 atoms

Now, we find the mass of aluminum that contains this number of atoms: Mass of aluminum = (number of atoms of aluminum × molar mass of aluminum) / Avogadro's number = (6.640 × 10^23 atoms × 26.98 grams/mole) / (6.022 × 10^23 atoms/mole) ≈ 29.99 grams

So, approximately 29.99 grams of aluminum contains twice as many atoms as 35.00 grams of copper.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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