What is your apparent weight?

Answer 1

The total upward force on you is #890 N#.

Your normal #"weight" = m*g = 75 kg*9.8 m/s^2 = 735 N#.

The elevator creates a zero net force when it is at rest or moving at a constant speed because the floor exerts an upward 735 N force.

You are accelerating upwards at #2 m/s^2#. The floor needs to provide an extra upward force to accelerate you upward at that rate. #"extra upward force" = m*a = 75 kg*2 m/s^2 = 150 N#
The total upward force on you is #(735 + 150) N = 885 N#. That is your apparent weight. In accordance to the number of significant digits in the data supplied, the answer should be reported as 890 N.

Alternatively, you could simply multiply your mass by (9.8 + 2 m/s^2), but I think that going through the previous steps clarifies the reasoning.

Hope this is helpful, Steve.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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