# What is there in the derivation of the Taylor/Maclaurin series for #sin(x)# that determines if the series assumes #x# is radians or degrees?

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But this is just a quick check. The actual proof might not be like this; I don't remember how it actually went.

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The derivation of the Taylor/Maclaurin series for sin(x) assumes that x is in radians. This is because the Taylor/Maclaurin series formulas are based on derivatives, and the derivatives of trigonometric functions like sin(x) are defined in terms of radians. Therefore, when using these series to approximate trigonometric functions, it's essential to ensure that the input values are in radians. If the input values are in degrees, they must first be converted to radians before using the series.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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