# What is the work done in lifting a 500-N barbell 2.2 m above the floor?

The work done by a constant force is given by the dot product:

Giving the familiar equation:

In raising the object, there is only the force which is being applied to cause the lift and the force of gravity acting against it.

Therefore, we can write:

We'll assume dynamic equilibrium (no acceleration but motion), giving:

The force of gravity acting on a stationary object at or near the surface of the earth is given by:

Which gives a new equation for work:

We are given the following information:

Since we're given the weight of the barbell, we'll have to find its mass first.

Therefore:

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The work done in lifting a 500-N barbell 2.2 m above the floor can be calculated using the formula:

[ \text{Work} = \text{Force} \times \text{Distance} ]

Substituting the given values:

[ \text{Work} = 500 , \text{N} \times 2.2 , \text{m} ]

[ \text{Work} = 1100 , \text{J} ]

Therefore, the work done in lifting a 500-N barbell 2.2 m above the floor is 1100 joules.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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