What is the volume of the container needed to store 0.8 moles of argon gas at 5.3 atm and 227°C?

Answer 1

Henry Antrim

#=6.19L#

As per the Ideal Gas Equation, we can

#PV=nRT#

Where

When we enter the gas equation, we obtain

#5.3V=0.8xx0.082xx500#

#V=(0.8xx0.082xx500)/5.3L=6.19L#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Olivia Anton

#V=(nRT)/P#

#V=(0.8*molxx0.0821*L*atm*K^-1mol^(-1)*500*K)/(5.3*atm)#

#=# #??L#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 3

Serenity Allen

Use the ideal gas law: ( V = \frac{{nRT}}{{P}} ) Where:

( V ) is the volume,
( n ) is the number of moles (0.8 moles),
( R ) is the ideal gas constant (0.0821 L·atm/(mol·K)),
( T ) is the temperature in Kelvin (227°C + 273.15),
( P ) is the pressure (5.3 atm).

Substitute values and solve for ( V ).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.