What is the volume of a #40 " m"xx20 " m"xx12 " m"# room in cubic feet?

Answer 1

#3.39xx10^5 " ft"^3#

You must first obtain the meters to feet conversion factor:

#1 " m"=3.281 " ft"#

Next, transform each room's edge as follows:

length = #40 " m"xx(3.281 " ft")/(1 " m")=131 " ft"#
width = #20 " m"xx(3.281 " ft")/(1 " m")=65.6 " ft"#
height = #12 " m"xx(3.281 " ft")/(1 " m")=39.4 " ft"#

Next, ascertain the volume:

volume = length #xx# width #xx# height
volume = #131 " ft"xx65.5 " ft"xx39.4 " ft" = 3.39xx10^5 " ft"^3#
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Answer 2

To convert cubic meters to cubic feet, multiply the volume in cubic meters by 35.315. So, the volume of the room in cubic feet is:

(40 \text{ m} \times 20 \text{ m} \times 12 \text{ m} \times 35.315 \approx 84728.8 \text{ cubic feet}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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