# What is the volume in milliliters of a 5.01 M silver nitrate solution that contains 275. mmol of silver nitrate?

54.9 ml

When 1000 mmol are in a mole, 275 mmol is equal to 275 mmole, or 0.275 moles.

There are 5.01 moles per liter in a 5.01 M solution.

With 0.275 moles, we have:

Thus, we get: 0.0549 x 1000 = 54.9 milliliters.

This is a fraction question, and the chemistry is most likely what's confusing people.

When I asked how much cake you had, after telling you that it had been cut into six slices and giving you one slice, you would respond, "1/6."

I have given you 0.275 of a slice of the cake that is divided into 5.01 slices in the question above (yes, I am aware that we can't really do that).

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To find the volume of the silver nitrate solution, you can use the formula:

Volume (in milliliters) = Number of moles / Molarity

Given: Number of moles of silver nitrate = 275. mmol Molarity of the solution = 5.01 M

Substitute the values into the formula:

Volume = 275. mmol / 5.01 M

Volume ≈ 54.89 milliliters

Therefore, the volume of the 5.01 M silver nitrate solution that contains 275. mmol of silver nitrate is approximately 54.89 milliliters.

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Volume = (moles of solute) / (molarity) Volume = (275 mmol) / (5.01 M) Volume ≈ 54.89 mL

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