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What is the vertex of # y=x^2 - 8x - 3 #?

Answer 1

The Solution set(or vertex set) is: #S = {4,-19}#

The general formula for a quadratic function is: #y = Ax^2 + Bx + C#

To find the vertex, we apply those formulas: #x_(vertex) = -b/(2a)# #y_(vertex) = - triangle/(4a)#

In this case: #x_(vertex) = - (-8)/(2*1) = - (-4) = 4# and #y_(vertex) = - (b^2 -4ac)/(4*1) = - (64 - 4 * 1 * (-3))/4# #y_(vertex) = - 76/4 = -19#

So, the Solution set(or vertex set) is: #S = {4,-19}#

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Answer 2

Savannah Anderson

To find the vertex of the quadratic function y = x^2 - 8x - 3, use the formula:

x-coordinate of the vertex = -b/(2a) y-coordinate of the vertex = f(-b/(2a))

Where 'a' is the coefficient of the x^2 term, and 'b' is the coefficient of the x term.

In this case: a = 1 b = -8

Substitute these values into the formula:

x-coordinate of the vertex = -(-8)/(2*1) = 4 y-coordinate of the vertex = (4)^2 - 8(4) - 3 = 16 - 32 - 3 = -19

Therefore, the vertex of the function y = x^2 - 8x - 3 is (4, -19).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.