What is the vertex of # y= x^2 - 4x - 3#?
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The vertex of the quadratic function ( y = x^2 - 4x - 3 ) is (2, -7).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you factor and solve #x^2 - 10x = -16#?
- How do you solve the quadratic equation by completing the square: #x^2 - 8x = 7#?
- How do you solve #x^2+7x+10=0#?
- How do you write a quadratic function in vertex form whose graph has the vertex (-4,-2) and point (-3,-1)?
- If #alpha# is a root of #x(2-x) = 3# then can you define a cubic equation with integer coefficients and roots including #-2# and #alpha# ?

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