What is the vertex of # y= x^2–3x- 12#?

Answer 1

Vertex (3/2, -57/4)

x-coordinate of vertex: #x = -b/(2a) = 3/2# y-coordinate of vertex: #y(3/2) = 9/4 - 9/2 - 12 = -9/4 - 48/4 = -57/4# Vertex #(3/2, -57/4)# graph{x^2 -3x - 12 [-40, 40, -20, 20]}
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Answer 2

The vertex of the quadratic function (y = x^2 - 3x - 12) is located at the point ((h, k)), where (h) is the x-coordinate and (k) is the y-coordinate. The x-coordinate of the vertex can be found using the formula (h = -\frac{b}{2a}), where (a) is the coefficient of (x^2) (1 in this case) and (b) is the coefficient of (x) (-3 in this case). Once you find the value of (h), substitute it back into the equation to find the value of (k).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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