Home > Algebra > Quadratic Functions and Their Graphs

What is the vertex of #y=4x-x^2#?

Answer 1

Eva Adamson

(2,4)

#(-b)/(2a)# gives the X coordinate of the vertex

#(-4)/(2xx-1)=(-4)/(-2)=2#

Put x=2 into #y=4x-x^2#

#y=4xx2-2^2#

#y=8-4. => y =4#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Genesis Allen

To find the vertex of the quadratic function ( y = 4x - x^2 ), you can use the formula:

[ x_{\text{vertex}} = \frac{-b}{2a} ]

Substitute the coefficients ( a = -1 ) and ( b = 4 ) into the formula:

[ x_{\text{vertex}} = \frac{-4}{2(-1)} = 2 ]

Then, substitute ( x = 2 ) into the original equation to find the ( y )-coordinate:

[ y = 4(2) - (2)^2 = 8 - 4 = 4 ]

Therefore, the vertex of the function is ( (2, 4) ).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.