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What is the vertex of # y= 4(x+2)^2-2x^2-4x+3#?

Answer 1

#(-3,1)#

Firstly, expand the squared brackets: #y=4(x^2+4x+4)-2x^2-4x+3# Then, expand the brackets: #y=4x^2+16x+16-2x^2-4x+3# Collect like terms: #y=2x^2+12x+19# Use formula for x-turning point: (#-b/{2a}#) thus, x=#-3# Plug -3 back into the original formula for y coordinate: #4(-3+2)^2-2(-3)^2-4(-3)+3=4-18+12+3=1# therefore the vertex is: #(-3,1)#

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Answer 2

Avery Alexander

The vertex of the function ( y = 4(x+2)^2 - 2x^2 - 4x + 3 ) is (-2, 3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.