What is the vertex of #y=3x^2-7x+12#? What are its x-intercepts?
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The vertex of the parabola represented by the equation y = 3x^2 - 7x + 12 is (7/6, 59/12). To find the x-intercepts, set y = 0 and solve the quadratic equation 3x^2 - 7x + 12 = 0. The solutions are approximately x ≈ 2.08 and x ≈ 1.45. Therefore, the x-intercepts are approximately (2.08, 0) and (1.45, 0).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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