What is the vertex of y=3x^2+6?

Answer 1

#(0,6)#

This is a 2nd degree quadratic function so its graph will be a parabola. Such function of form #y=ax^2+bx+c# has turning point at #x=-b/(2a)#, so in this case at #x=0# which implies corresponding y-value is at the y-intercept itself of #6#.

As proof, see the graph below:

graph{3x^2+6 [-40.64, -4.72, 27.74]}

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Answer 2

The vertex of the function y = 3x^2 + 6 is (-0.0, 6.0).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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