What is the vertex of # y= 2x^2+5x-13-4(x-1)^2#?

Answer 1

The vertex is #(13/4 , 33/8)#.

We expand and combine like terms: #y = 2x^2-4x^2+5x+8x-13-4 = -2x^2+13x-17# The x-coordinate of the vertex is: #x = -\frac{b}{2a} = 13/4 = 3 1/4# #y = 33/8 = 4 1/8# Therefore, the vertex is #(13/4 , 33/8)#.

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Answer 2

Ethan Adkins

The vertex of the given quadratic function ( y = 2x^2 + 5x - 13 - 4(x - 1)^2 ) is (-1, -17).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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