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What is the vertex of #y= 2x^2+16x + 12#?

Answer 1

vertex: #(x,y)=(-4,-20)#

Convert the given: #y=2x^2+16x+12# into general vertex form: #y=color(green)(m)(x-color(red)(a))^2+color(blue)(b)# with vertex at #(color(red)(a),color(blue)(b))#

#y=2(x^2+8x)+12

#y=2(x^2+8xcolor(blue)(+4^2))+12 color(blue)(-2(4^2))#

#y=2(x+4)^2-20#

#y=color(green)(2)(x-color(red)(color(white)("")(-4)))^2+color(blue)(color(white)(""X)(-20))#

#color(white)("XXXXXX")#with vertex at #(color(red)(color(white)("")(-4)),color(blue)(color(white)("")(-20)))# graph{2x^2+16x+12 [-16.64, 8.68, -21.69, -9.03]}

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Answer 2

Hazel Anglin

The vertex of the quadratic function y = 2x^2 + 16x + 12 is (-4, 4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.